gfun[minimizediffeq] minimize differential equation given initial conditions

Calling Sequence

minimizediffeq(deq, y(z), options)

Parameters

deq - a set containing a linear differential equation with polynomial coefficients and initial conditions specifying a unique solution of it;

Description

Examples

> with(gfun):
> deq:={(20*z^6+12*z^5)*y(z)+(4*z^7+z^2+3*z-9)*diff(y(z),z)+(z^3-3*z^2)*diff(diff(y(z)
,z),z), y(0) = 1};
\[\{\left(20 z^{6}+12 z^{5}\right) y \! \left(z \right)+\left(4 z^{7}+z^{2}+3 z -9\right) \left(\frac{d}{d z}y \! \left(z \right)\right)+\left(z^{3}-3 z^{2}\right) \left(\frac{d^{2}}{d z^{2}}y \! \left(z \right)\right), y \! \left(0\right) = 1\}\]
> minimizediffeq(deq,y(z));
\[\{4 z^{5} y \! \left(z \right)+\left(z -3\right) \left(\frac{d}{d z}y \! \left(z \right)\right), y \! \left(0\right) = 1\}\]
> deq:={z^2*(1+z)*diff(diff(diff(y(z),z),z),z)-z*(2*z^2+2*z-1)*diff(diff(y(z),z),z)+(-
z^2-4*z-1)*diff(y(z),z), y(0) = 0, (D@@2)(y)(0) = 1/4};
\[\left\{z^{2} \left(1+z \right) \left(\frac{d^{3}}{d z^{3}}y \! \left(z \right)\right)-z \left(2 z^{2}+2 z -1\right) \left(\frac{d^{2}}{d z^{2}}y \! \left(z \right)\right)+\left(-z^{2}-4 z -1\right) \left(\frac{d}{d z}y \! \left(z \right)\right), y \! \left(0\right) = 0, D^{\left(2\right)}\! \left(y \right)\! \left(0\right) = {\frac{1}{4}}\right\}\]
> minimizediffeq(deq,y(z));
\[\left\{\left(-z^{2}-4 z -1\right) \left(\frac{d}{d z}y \! \left(z \right)\right)+\left(-2 z^{3}-2 z^{2}+z \right) \left(\frac{d^{2}}{d z^{2}}y \! \left(z \right)\right)+\left(z^{3}+z^{2}\right) \left(\frac{d^{3}}{d z^{3}}y \! \left(z \right)\right), y \! \left(0\right) = 0, D^{\left(2\right)}\! \left(y \right)\! \left(0\right) = {\frac{1}{4}}\right\}\]

So this equation is already minimal. However, the solution also satisfies a non-homogeneous equation of smaller order:

> minimizediffeq(deq,y(z),false);
\[\left\{\left(-z^{2}-4 z -1\right) \left(\frac{d}{d z}y \! \left(z \right)\right)+\left(-2 z^{3}-2 z^{2}+z \right) \left(\frac{d^{2}}{d z^{2}}y \! \left(z \right)\right)+\left(z^{3}+z^{2}\right) \left(\frac{d^{3}}{d z^{3}}y \! \left(z \right)\right), y \! \left(0\right) = 0, D^{\left(2\right)}\! \left(y \right)\! \left(0\right) = {\frac{1}{4}}\right\}\]

See Also

LREtools[MinimalRecurrence], gfun